Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Updated On: 9-4-2020

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Loading DoubtNut Solution for you

Watch 1000+ concepts & tricky questions explained!

70.0 K+

57.8 K+

Text Solution

Solution :

Let PQ be a tower of height 15 m. Two points A and B are on the same side of a tower. <br> Given that `angleXPA=60^(@)rArranglePAQ=60^(@)` (alternate angles) <br> and `angleXPB=45^(@)rArranglePBQ=45^(@)` (alternate angles) <br> Let AQ = x and AB =y m <br> In right `DeltaPQA` <br> `tan60^(@)=15/xrArrsqrt3=15/xrArrx=15/sqrt3` <br> `rArr x=15/sqrt3xxsqrt3/sqrt3=5sqrt3 m ...(1)` <br> In right `Delta PQB`, <br> `tan45^(@)=15/(x+y)rArr1=15/(x-+y)rArrx+y=15 ...(2)` <br> `:.` From wquations(1) and (2), distance between two points A and B is <br> `y=x+y)-x` gtbrgt `=(15-5sqrt3)m` <br> `=(15-5xx1.732)m` <br> `=6.34m` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NTN_MATH_X_C09_S01_014_S01.png" width="80%">